#!/usr/bin/python
########################################################################
#
#  Copyright 2002, Tero Tilus <tero@tilus.net>
#
#  This software is distributed under the terms of the GNU general
#  Public license <http://www.gnu.org/licenses/gpl.html> and WITHOUT
#  ANY WARRANTY.
#
########################################################################

# Takes list of css -files as arguments.  Prints sorted combination of
# files with duplicate css-entries removed.  Only string-comparison is
# made between entries, so css-files MUST have same (canonical)
# format.  If they don't a css pretty-printter (if you can find one)
# may help.

import sys
import string

def main(args):
    cssfiles = args[1:]

    if ( len(cssfiles) < 1 ):
        print 'Usage: ' + (string.split(args[0],'/')[-1]) + \
              ' file1.css [file2.css ...]'
        return 1

    entries = []
    for cssfilename in cssfiles:
        cssfile = open(cssfilename, 'r')
        tmpentries = string.split(cssfile.read(), '}')
        for tmpentry in tmpentries:
            tmpentry = string.strip(tmpentry)+'\012}'
            if ( entries.count(tmpentry) == 0 ):
                entries.append(tmpentry)
        cssfile.close()

    entries.sort()

    for entry in entries:
        print entry+'\012';

    return 0

main(sys.argv)